### Challenge Picture

9:14 PM

Hey Everyone, hopefully this helps!!

### Challenge!!!

12:38 PM

Hey Everyone! I'm not sure if Mr. H want's me to write here, {please let me know if this is bad haha} but my name is Chantelle and I am going to the U of Regina and have been invited to your Blog!!!

I came across a question in one of my math classes that I feel will be right up your alley with Pythagorean Theorem! So here is a little challenge for you!
The question is: The perimeter of an isosceles triangle {2 sides are equal and the two angles at the base are equal} ABC with AB=BC is 128 inches. The altitude {height of the triangle which is perpendicular (90 degree angle) to the base ( and in the case of an isosceles triangle, hits at the midpoint of the base)} BD is 48 inches. What is the area of the triangle??

So, you will need a couple formulas other than just pythagorus. However, I think you can do it!
This is from my Math 308 class, which is a 4th year math class!!!

Good Luck!!

### Scribe post for March 10, 2009

6:39 PM

Today in class we still talk about squares but we also learned how to cut them into equal pieces. We used tiles to make them in eqaul pieces.

I am gonna make some examples of how to cut them into equal pieces.

I dont know how to explain it in words so I am just going to put some more pictures as examples.

all you do is basicly cutting them in equal pieces.

I hope that you have understood what i have done. Sorry for any mistakes I have made. PLEASE leave a comment.I choose ANYONE who wants to do the next scribe.

### Scribe Post for March 9, 2009

8:45 PM

Today in class we made a times table (12x12). We made this on grid paper and made a chart along with the times table called the Perfect Square Chart.

On the times table, we were suppose to color the numbers that would make a perfect square which would be in a diagonal. And color the other numbers with different colors, like so

And here is the Perfect Square Chart. In this chart it has the number squared, the factors, and the answer.

We also had to answer "to be in the Perfect Square club you must be..." and "if you don't belong to the perfect square club you..."

I answered these the best I could.
1.) To be in the Perfect Square club you must be a whole number meaning you cannot have a decimal.

I hope that you have understood what i have done. Sorry for any mistakes I have made. PLEASE leave a comment. I choose Andrew to do the next scribe.

### Scribe Post

6:39 PM

Today we did some math,and i will be showing the question,Mr.Harbeck just teach use a bit then he went somewhere.

a2+b2=c2
23 squared+36 squared=c2
529+1290=c2
1825=c2
√ 1828 √ c2
42.720=c
40.700

A rectangle has a perimeter of 32cm,the length of the field is 5 meters more than twice the
width.Find the diameters of the field
*Solve using Algebra method. Draw diagram

Next one is..
__6__ out comes with trains.
the probability of C,T,F is __1/18__ which is 5.59 repeated
C, R , V they all both have 6.

### Scribe Post for March 3, 2009

8:20 PM

So today we corrected right angle problems and the mean, median, and mode problem. Then, we were given 3 problems to solve using the Pythagoras theorem. TEST : THURSDAY. These problems will help you better on the test.

By the way, √ <-- this means the square root. Question 1:
a^2+b^2=c^2
a^2+2^2=8^2
-2^2 -2^2
a^2=8^2-2^2
a^2=64-4
a^2=60
√a^2=√60
a=7.745

Question 2:

a^2+b^2=c^2
a^2+13^2=20^2
-13^2 -13^2
a^2=20^2-13^2
a^2=400-169
a^2=331
√a^2=√331
a=18.193

Question 3:

a^2+b^2=c^2
6^2+b^2=23^2
-6^2 -6^2
b^2=23^2-6^2
b^2=529-36
b^2=493
√b^2=√493
b=22.206

After, we were given these questions:

I can't really help you on this because I don't understand the last 2 questions.

But the first questions answer is : 1/3

Thank you for reading! Tomorrow is my last day! Comment!

### Scribe Post for March 2

7:55 PM

The Following times were recorded, in seconds. For the runners in a race.
20.2, 16.5, 40.4, 18.5, 21.4, 20.5, 17.1, 24.5, 19.0
What is the range of the times?
What are the mean and median of the times?
Identify any possible outliers. Should the Outlier(s) be removed from the data set?

The first thing you should do is arrange the data set in ascending order.

16.5, 17.1, 18.5, 19.0, 20.2, 20.5, 21.4, 24.5, 40.4
to get the range you must take the greatest number and subtract the least from it.
Greatest - least = range
40.4 - 16.5 = 23.9

Next we will find the median this is where the ordering in ascending order comes in handy.
You have to find the middle number one way is to get rid of the ends so until you only have one or two numbers in the middle.

To get the mean you need to add up all the numbers in the data set and divide by how many numbers in the data set.

sum of all data 198.1
_________________ = 22.01

number of data 9

last we will find the outlier if there is one an outlier is a number that doesn't fit in in this case all the numbers are less than 25 but one which is 40.4 it is an outlier. sometimes an outlier will kill the set of data and destroy the mean with the outlier the mean is 22.o1 without the outlier it is 19.71 Sometimes it is smart to take out the outlier before finding the mean. For example it is smart to take it out so it doesn't completely mess up the mean.

we also did some triangles here are two of them of them.