Showing posts with label Integers. Show all posts
Showing posts with label Integers. Show all posts

Vikram's Big Book of Algebra

10:07 PM

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Chapter 1:

(Haiku)

Adding is easy

so easy will make you laugh

Add with the brackets

(Tanka)

Subtraction is fun

You will take away numbers

Take away, Minus

Subtraction does not exist

You Shall add the opposite


(Free Verse)

Take a deck of cards

Give them equally out

to everyone there

until you have no

more cards

(Haiku)

Hard but fun to learn

Negatives and Positives

Easy after learned


(Free Verse)

If there are a even amount

of negative or integers the

sum will be positive

If there is a odd amount of

negative integers the

product shall be negative

If a zero is involved the

product shall be a zero



Chapter 2: (xtra normal did not work)

Yusei: I am ready for any questions you got.
Jack: Oh really?
Yusei: Yes
Jack: Try this one then
Jack: n+3-5n+12.
Yusei: Sure give me a few minutes.
Jack: Okay.
Yusei: The answer is -6n+15.
Jack: Wrong, now take a few minutes to figure out the right answer.
Yusei: okay...
Yusei: I know where I went wrong, I added the n to the -5n. But I should have subtracted the n from the -5n. Which makes it -4n+15.
Jack: Yes young one.
Yusei: See I'm good.
Jack: But you still have a second question.
Yusei: ahh...
Jack: here it is. 2 + 4(3n+8)
Yusei: This is a harder one... give me some more time.
Jack: Okay
Jack: ( 10 minutes later) Are you done yet?
Yusei: I've been done 8 minutes ago.
Jack: Then what were you doing?
Yusei: Watching Television.
Jack: What ever, so what is your answer?
Yusei: 12n + 10!
Jack: Wrong
Yusei: ahh man.
Jack: Here is the right answer
Jack:12n + 34
Yusei: hmm....
Jack: Oh, you already know your mistake?
Yusei: Yes I do...
Jack: Okay what is it?
Yusei: I forgot to multiply 8 by 4 , then add the extra 2, which would have made 34.
Jack: Very well done.
Yusei: Hmm? but I got all the questions wrong.
Jack: But you found what your mistakes were.
Jack: That is what math is all about, learning from your mistakes.
Yusei: I get it now...
Jack: That is what matters
Jack: Well I'm off
Yusei: c ya
Jack: bye
Yusei: ...














Vikram 9-05

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scribe post for november 26

4:58 PM

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Scribe Post for November 26, 08 by Louisse



Yesterday we did ten questions with solutions.
I'm going to show you the answers and solutions for the first four questions

-Here is the fisrt question.














here is the solution.........


-first you need to add the first 2 numbers
-3+(-5)-11=
-copy the answer of the first two numbers then bring down the rest of integer numbers.
-8-11=-19
so you can understand it a little bit better you can look at the picture.















-so that is one way to do the question..


-here is the second question, but this question is a little bit harder to explain.

so I'm just going to show you picures.


(Question#2)














solution..














-here is the third question..























THE SOLUTION IS....

first you need to multiply the first two numbers(6(-2)=-12)then you need to multiply the second two numbers.

second you need to multiply or add(it depends on the question) the numbers under it.
if you got the answers you need to divide it.








-here is the fourth question

















THE SOLUTION IS....
first, you need to add -5 and 19, then multiply 6 to -1, if you got the answer add it. after that, divide it to -4.
plsssss leave a comment!!!
for the next scribe I choose Bea

muriel 9-04

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Scribe Post for Nov.20, 2008 by Lance

5:08 PM

(11) Comments

Today in class we have discussed the Division of Integers. We talked about quadrants.

We also learned that there are 3 ways to write division statement.



To make division easier to understand there are two ways we can use the Quotative and Partitive.

Example:
12 ÷4= 3


Quotative




How many fours are there in twelve.
We have to circle three groups of four.

Partitive
How many equal parts are in four groups if we have 12.
We have to circle four groups of three.
12÷4=3
to check your answer
3×4=12
For the next Scribe I choose Christian.

lance8-73

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Scribe Post for November 19,2008 by Chie Visda

8:10 PM

(7) Comments

Today in class, we went over our work, the work we did the today . Heres what we did in class Division of Integers

Here's the new stuff

(Quotative)


(Partitive)


Then after, Mr. H gave us homework in Division of Integers.

-6/2 we have to put this in the right quadrant.

And for the next Scribe I chose Lance.
 Please leave a comment!

Chie8-73

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4:25 PM

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Scribe Post for November 13, 2008

Today in class checked our homework (green booklet pg. 5, 13-18) to make sure our answers are right. We spent most of the class on this. Since you already know the rules/theorem for multiplying integers, I will talk about the "new" thing we learned in class.

We learned what to do with questions like this:

Since there is no sign between the -2 and the bracket, that means you have to multiply. To solve this question, put the -2 in brackets:




Then solve the question like you would normally. Remember, there is an even number of negative integers in this question so the product will be positive.



The answer to this question is +6.



We also learned how to solve questions where the negative sign is outside the bracket. Like this:


That negative sign, all by itself means -1. So the question will now look like this:


(-1)(2)= -2 . Now we answer the rest of the question:
You can also do it this way:

When you see a negative sign beside a bracket (uh-oh) you change the integer to a positive.


Well that's all for today. Remember, homework is the green booklet pg. 5, questions 19 - 36. I hope my pictures weren't too bad ;). I choose Elmane as the next scribe. Please leave comments. Thanks for reading!

explorer9-05

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Scribe Post for November 12, 2008

4:38 PM

(9) Comments

Today we corrected our homework (green booklet pg. 5, 1-12). We spent almost half the class time on correcting it. Here on the scribe post I wouldn't bother with yesterdays homework. Instead I'm going to scribe about the multiplication rules. Then would scribe about Mel's Integer Theorem. Last but not least, the homework for today.

So, here we go. These are the multiplication rules/theorem. With positive and negative integers.
For the first one, the answer is negative. The next question however, you could use the previous question.Then just multiply the rest with the answer from the previous question. That was the pattern Mr. H was looking for. For me I did it a different way. It took longer, especially explaining it during class.

This is another multiplication rule/ theorem. Here it is only including negative integers.

For this theorem I have a formula using exponents. Here it is.





These formulas are just explaining Mel's Integer Theorem.

This is Mel's Integer Theorem.

When you multiply integers and there are an even amount of negative integers the product is positive.

When you multiply integers and there are an odd amount of negative integers the product is always negative.

Today's homework is to prove Mel's Integer Theorem. We are suppose to prove it by answering questions 13- 18, pg 5, green booklet. I would show 13 and 14 to you.



13.

14.

That's all for today people. Don't forget to do your homework.For the next scribe I choose Kristin. Thanks for reading my scribe post and please leave a comment.

angela905

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Scribe Post For Nov 10. 2008

6:01 PM

(10) Comments

Today in class the first thing we did was look over our homework which was done in the blue barn yard.

Then he gave us homework from page 5 in the green booklet. He made us pick 4 questions and each and to be from the coordinate chart and we had to illustrate them. The other eight we just had to write the answer. Here are the 4 I picked.

1) (3)(9)=

Which is from the quadrant 1 and it means 3x9. Here's how I answered it...


This represents 3 groups of 9 which equals to 27.

2) (-12)(3)

This question is from quadrant 2. Here's how I answered it....


This represents 3 group of- 12 getting removed. The answer equals to - 36.

3) (6) (-2)

This question is from quadrant 3. Here's how I answered it...

This shows 6 groups of -2 which equals to -12.

4)(-5)(-4)

This question is from quadrant 4. Here's how I answered it.

This shows -5 groups of -4 getting removed, which equals to +20.

He also gave us homework to find the pattern, what we noticed, to make a rule and anything else for this...
This is how I answered it.

(-)(-)=positive

(-)(-)(-)=negative

(-)(-)(-)(-)=positive

(-)(-)(-)(-)(-)=negative

(+)(-)= negative

(+)(-)(-)=positive

(+)(-)(-)(-)=negative

(+)(-)(-)(-)(-)=positive


The rule when multiplying a negative integer with a negative integer the product is always a positive. When multiplying a positive integer with a negative integer the product always equals to a negative.

The patterns I noticed were that the answers were positive then negative and vice versa. Each time you went down they would add a second integer.



For the next scribe I pick Angela. Thanks and please leave a comment. :)

simran 9-05

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Scribe Post for November 5, 2008

4:25 PM

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Today in class, we talked about multiplying integers. We were recorded by the smart board. Mr. Harbeck and Mr. Baché gave us 2 pieces of paper. One was blue and the other one was white. (we only used the blue paper for today.) We had to fold it and make it into eight squares. We opened it up and only kept the 2 flaps folded in. We cut on the middle of the paper so there
would be 4 doors, 2 at the top and 2 at the bottom. At the end, it should look like this:

















On the first flap (++) we opened it and wrote:

(+2)(+3)

When brackets are touching we multiply

Make two groups of 3.














For homework in our (++) Multiplying Integers Sheet (blue) we had to make up a question draw a picture here is what I did:


(+3)(+5)

For next scribe I choose Shaneille. So I guess I am done now. Thanks for reading my scribe post. Please leave a comment!

Zerlina905

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Scribe Post for November 4, 2008

5:33 PM

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Today in class, we went over questions from yesterday's homework, that people had difficulties with. For example, one of those questions were Question #10, in Part Three. People found this question difficult, because there is a subtraction sign by itself in the beginning of the question.

But before I explain how to solve Question #10, I'll go over the steps on how to solve questions that have more than one integer in the brackets.


Okay, now I'll explain how to do Question #10, in Part Three.

After Mr. Harbeck went through all those questions, he taught us how to solve questions that have discountonall square brackets. Those brackets look like these --> [ ]

When solving these kinds of questions, the steps are a little different, compared to the steps on how to solve questions with more than one integer in the brackets.

1. solve inside the round brackets

2. solve inside the square brackets

*when you've finished solving inside the square brackets, you should be left with only one integer*

3. rewrite the question
  • keep the brackets
  • pull down all the order of operation signs

4. get rid of the "uh-oh's" by changing it into an addition sign

5. rewrite the question in standard form

6. solve

These are two examples of questions that have square brackets.

Example #1 -


Example #2 -


For homework, we need to finish Part Four, and Page 12 (AKA last page). Also, you need to pick any 10 questions from Pg. 12, and in your scribbler, rewrite them in standard form.
That's about everything we did in class today.
For tomorrow's scribe, I pick Zerlina.
Thanks for reading my scribe, and please leave a comment (:

melanie905

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Scribe Post for November 3 2008

5:13 PM

(6) Comments

Today we had to do a few problems from the green booklet. We have to do questions that are similar to the questions from Part 3 (which coincidentally is our homework).

The difference in these questions are that you'll need to do BEDMAS.

For example, if you take question... I don't know... 13.

13. (17-25) - (-8+7) - (-15+25)


First Step: Do the INSIDE of the brackets.



13. (17-25) - (-8+7) - (-15+25)
-8 -1 10

Second Step:Keep the brackets

13. (17-25) - (-8+7) - (-15+25)
(-8) (-1) (10)

Third Step: Pull down order of operations sign

13. (17-25) - (-8+7) - (-15+25)
(-8) - (-1) - (10)

Fourth Step: Look for "uh-oh"s (and turn them into have have)

13. (17-25) - (-8+7) - (-15+25)
(-8) + (+1) - (10)

Fifth Step: Rewrite (and look for shortcuts like zero pairs because we're "lazy teenagers")

13. (17-25) - (-8+7) - (-15+25)
(-8) + (+1) - (10)
-8+1-10



Sixth Step: Combine like integers

13. (17-25) - (-8+7) - (-15+25)
(-8) + (+1) - (10)
-8+1-10
-18+1 =+17


10. -(-2+8) + (-3-4)








3. (-2+4) - (-4+2)=

( 2 ) - ( -2 )

(2) + (+2)

2+2=4

Homework

1. Part 2. odd numbers only (if you haven't done them already)

2. Part 3. All of it.

I pick Melanie to do the next scribe.

allie

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scribe post for october 30th, by Azra

11:55 AM

(3) Comments

we learn in math class about integers. Positive and about negative integers. First we learn how to add integers, here some example for positive integer, first we have to know something
(+) + (-) = (-)
(-) + (-) = (+)
(+) + (+) = (+)

some example for positive integers



(+3) + (+9) = (+12)



(+5) + (+5) = (+10)



(+2) +( 4) = (+6)



(+4) + (+9) =(+13)



and then we do more positive integer



earn 30 doller lose 5 doller = left (+25) or 25 doller



have 5 orange lost 2 orange = left 3 orange






then we lern about how to draw integers time line I will show you time line pictures after first I want to show you how can we subtract integers, some example are



(-5) - (-9)



=(-5) + (+9) = (+4)



(-8) - (+6)



=(-8) + (-6) = (-14)



(-2) - (0)



= (-2)



Now I want talk about 0 pairs, some example for 0 pairs



(-6) + (+6) = (0)



(+100) + ( -100) = (0)



(+1000) + (-1000)= (0)



we did stenderd form in integers like



-2 -9 =-11



=+6 -7 = -1






-6 +2 - (-2)+ 3



=-6 +2 + (+2) +3



=-6 +7



=+1






we had quiz about negative and positive integers, like



(+9) + (+6) = (+15)



(+2) + (0) - (-4)



(+2) + (0) + (+4)



(+6)






(-5) - (-5)



= (-5) + (+5)



= (0)






(+6) + (+9) - (-4) - (-8)



=(+6) + (+9) + (+4) + (+8)



=(+27)


more about integers



rises 3 degree drop 2 degree = left 1degree



have 50 books give a friend 10 books = left 40 books




now I want to talk about time line, how can we add integers in time line



(+2) + (+1) = (+3) in time line













azra873

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Scribe post for Oct.30,2008 by shaine

6:58 PM

(2) Comments

Today in class Mr.Harbeck gave us a green booklet,and we tackled about adding and subtracting integers in standard form. For our homework Mr.Harbeck assigned us to do the part 1 (1-20) and part 2 (even numbers only).


In some cases in the part 2 , you should re-write the question first and then add the opposites
and you must also have to remove the "diapers" or parenthesis or something like Mr.Harbeck said...

e.g.
1.) 8 - (-7) + 3 - (-5) = ?
have8 owe owe7 have3 owe owe5 = ?
8 + 7 + 3 + 5 = 23
have8 have7 have3 have5 = have23

but in part 2 you only have to do the even numbers.....

2.) 5 - (-8) - (7) + 5 = 25

4) 5 - 2 - (-7) - (-3) = 13

6) -7 - (-5) - (-7) - 8 = -3

8) -7 - (-5) - (5) + 8 = 11

10) - (-2) - (-6) - 15 = -7

12) -2 - 3 + 4 - 6 = -7

14) 2 - 7 - 8 = -13

16) 3 - 8 + 9 = 2

18) - 20+ (-8) - 4 - (-10) = -6

20) -100 - (-100) + 50 - (-50) = 100

22) -10- (-10) -1 =1

24) - (-5) + 9 - 20 = -6

shaine873

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Scribe post for October 30 By Vikram

6:48 PM

(1) Comments

Today in class we learned about how to do math in standard form. Instead of the regular integers with a *+* and *-* sign. He even gave us a new green booklet. The green booklet looked like the old grades but with a negative sign on some of the numbers. The old way our integer questions were before was at a grade 7 level.
<---- G 7 level.


The grade 8 level looks different and a little harder. it looks like this
<------Grade 8 level



You can see that the math questions look harder with out the brackets. Well here is a way to make life easier for you. If the question reads like this 6 - (-4) Have 6 owe owe 4 you switch the opposite so its 6 + (+4) which reads, have 6 and have 4. Here are some questions.

6+8 = 14

-4 - 3 = -7

14+8 = 22

-11 + 12 = 1

-50 - (100) = -150

For he next Scribe post I choose no one :P

Vikram 9-05

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Scribe post for Oct.30,2008 by Bea

5:16 PM

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This afternoon we have taken in math is the adding and subtracting integers in standard form you only have to do is like this 6+8 or have 6 have 8 not the other type of adding and subtracting integers that have an and like have6 and have 8 this is like the adding of the kindergarten.

Part #1

1) 6+8=14
2) -4-3=-7
3)15-2=13
4)14+8=22
5)9-23=-14
6)-5-8=-13
7)-12+25=13
8)-11+12=1
9)22-8=14
10)-7-8=-15
11)-4+4=0
12)-8-9=-17
13)6-9=-3
14)11-(8)=3
15)5-12=-7
16)-8+3=-5
17)-6+3-12-1=-16
18)-1+18-7+2=12
19)-8+5-7=-10
20)-10-3+8-2=-7

Part #2

2)5-(-8)-(7)+5=25
4)5-2-(-7)-(-3)=-7
6)-7-(-5)-(-7)-8=13
8)-7-(-5)-(5)+8=1
10)-(-2)-(-6)-15=9
12)-2-3+4-6=11
14)2-7-8=-13
16)3-8+9=4
18)-20+(-8)-4-(-10)=-6
20)-100-(-100)+50-(-50)=100
22)-10-(-10)-1=1
24)-(-5)+9-20=-16
watch this how to do integers





bea873

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Scribe post for October 30,2008 by Chie Visda

4:58 PM

(1) Comments

Today in class, Mr.Harbeck assigned Part 1 and Part 2 in our Green Booklet For homework. So he decided to do the green booklet for homework.
On Green Booklet, Part 2,we have to use Adding and Subracting Integers

Your suppose to re-write and then you will make the minus to plus.



For Green Blooklet Part 2 Question 2-24 you could use Adding and Subracting Integer
For yellow booklet page 48 Question 15 you could use sum or difference.

15). (+15)+(-5)-(-7)
First you will do the addition of integers by adding (+15) and (-6) and this will give +9.
The sum 9 will give us +9.
The sum 9 will be subtracted to (-7) and in subtraction of integers we need to change the sign of the subtrahend so (-7) will become (+7), then we will proceed to addition of integers.



For Green Blooklet Part 2 Question 2-24 you could use Adding and Subracting Integer
For yellow booklet page 48 Question 15 you could use sum or difference.

Chie8-73

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