### Scribe Post for November 12, 2008

For the first one, the answer is negative. The next question however, you could use the previous question.Then just multiply the rest with the answer from the previous question. That was the pattern Mr. H was looking for. For me I did it a different way. It took longer, especially explaining it during class.

This is another multiplication rule/ theorem. Here it is only including negative integers.

For this theorem I have a formula using exponents. Here it is.

These formulas are just explaining Mel's Integer Theorem.

This is Mel's Integer Theorem.

When you multiply integers and there are an even amount of negative integers the product is positive.

When you multiply integers and there are an odd amount of negative integers the product is always negative.

Today's homework is to prove Mel's Integer Theorem. We are suppose to prove it by answering questions 13- 18, pg 5, green booklet. I would show 13 and 14 to you.

13.

That's all for today people. Don't forget to do your homework.For the next scribe I choose Kristin. Thanks for reading my scribe post and please leave a comment.

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Also thank you Ms. Skogberg for reading our blog.

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